(x-4)^2=-(1/3)*(y+5)

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Solution for (x-4)^2=-(1/3)*(y+5) equation: 


x in (-oo:+oo)

(x-4)^2 = -((1/3)*(y+5)) // + (1/3)*(y+5)

(x-4)^2+(1/3)*(y+5) = 0

(x-4)^2+1/3*(y+5) = 0

(x-4)^2+1/3*(y+5) = 0

x^2-8*x+1/3*y+53/3 = 0

x^2-8*x+1/3*y+53/3 = 0

x^2-8*x+1/3*y+53/3 = 0

DELTA = (-8)^2-(1*4*(1/3*y+53/3))

DELTA = 64-4*(1/3*y+53/3)

64-4*(1/3*y+53/3) = 0

64-4*(1/3*y+53/3) = 0

-4/3*y-20/3 = 0

-4/3*y-20/3 = 0

-4/3*y-20/3 = 0 // + 20/3

-4/3*y = 20/3 // : -4/3

y = 20/3/(-4/3)

y = -5

DELTA = 0  <=>  t_3 = -5

x = 8/(1*2) i y = -5

x = 4 i y = -5

( x = ((64-4*(1/3*y+53/3))^(1/2)+8)/(1*2) or x = (8-(64-4*(1/3*y+53/3))^(1/2))/(1*2) ) i y > -5

( x = ((64-4*(1/3*y+53/3))^(1/2)+8)/2 or x = (8-(64-4*(1/3*y+53/3))^(1/2))/2 ) i y > -5

y+5 > 0

y+5 > 0 // - 5

y > -5

x in { 4, ((64-4*(1/3*y+53/3))^(1/2)+8)/2, (8-(64-4*(1/3*y+53/3))^(1/2))/2 }

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